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【字體: 數(shù)據(jù)庫(kù)系統(tǒng)工程師全真預(yù)測(cè)試卷上午試題及參考答案
數(shù)據(jù)庫(kù)系統(tǒng)工程師全真預(yù)測(cè)試卷上午試題及參考答案
spks.exam8.com 來(lái)源:考試吧Exam8.com) 更新:2009-10-11 9:28:57 軟件水平考試 考試論壇
考試吧收集整理了數(shù)據(jù)庫(kù)系統(tǒng)工程師全真預(yù)測(cè)試卷上午試題及參考答案,2009年下半年軟考時(shí)間是2009年11月14日-11月15日。請(qǐng)及時(shí)觀注考試吧軟件水平考試欄目!考試吧祝各位順利通過(guò)本次考試!


  ●由于可重用資源的沖突會(huì)引起死鎖,產(chǎn)生死鎖有四個(gè)必要條件:互斥、保持和等待、循

  環(huán)等待以及_(42)_分配方式。

  (42)A.資源消耗性  B.資源非消耗性  C.不可搶占式  D.搶占式

  ●判斷線索二叉樹中某節(jié)點(diǎn)P有左孩子的條件是_(43)_。若由森林轉(zhuǎn)化得到的二叉樹是非空的二叉樹,則二叉樹形狀是_(44)_。

  (43)A.P!=null   B.p->lchild!=null  C.P->itag=0 D.p->itag=1

  (44)A.根節(jié)點(diǎn)無(wú)右子樹的二叉樹    B.根節(jié)點(diǎn)無(wú)左子樹的二叉樹

  C.根節(jié)點(diǎn)可能有左二叉和右二叉樹 D.各節(jié)點(diǎn)只有一個(gè)兒子的二叉樹

  ●多個(gè)并發(fā)進(jìn)程使用一個(gè)互斥信號(hào)量nap時(shí),如果rap=13,則通常表示_(3)_45) 。

  (45)A.有多個(gè)進(jìn)程在臨界區(qū)中  D.有一個(gè)進(jìn)程在臨界區(qū)中

  C.沒(méi)有進(jìn)程在臨界區(qū)中

  D.有一個(gè)進(jìn)程在臨界區(qū)中,另一些進(jìn)程正等待進(jìn)入臨界區(qū)

  ●IP操作主要解決三個(gè)問(wèn)題:_(46)_、_(47)_和_(48)_。

  (46)A.識(shí)別標(biāo)識(shí)號(hào)  B.尋址    C.網(wǎng)絡(luò)分組   D.名字翻譯

  (47)A.分段     B.修改路徑  C.路徑選擇  D.網(wǎng)絡(luò)連接

  (48)A.分段和重組  B.打包    C.產(chǎn)生數(shù)據(jù)段 D.目標(biāo)服務(wù)

  ●如果I/O設(shè)備與存儲(chǔ)設(shè)備進(jìn)行數(shù)據(jù)交換不經(jīng)過(guò)CPU來(lái)完成。這種數(shù)據(jù)交換方式是_(49)_。

  (49)A.程序查詢  B.中斷方式   C.DMA方式  D.無(wú)條件存取方式

  ●MIDI的音樂(lè)合成器有_(50)_。

 、貴M ②波表、蹚(fù)音 ④音軌

  (50)A.①   B.①②   C.①②③   D.全部

  ●在多媒體中記錄音樂(lè)的文件格式常用的有WAVE、MP3和MIDI等。其中WAVE記錄了音樂(lè)的_(51)_,MP3記錄了_(52)_的音樂(lè),MIDI記錄了_(53)_。在用MPEG格式存儲(chǔ)的圖像序列中,不能隨機(jī)恢復(fù)一幅圖像的原因是它使用了_(54)_技術(shù),影響這種圖像數(shù)據(jù)壓縮比的主要因素是_(55)_ 。

  (51)A.模擬信號(hào)電壓量   B.模擬信號(hào)的采樣數(shù)值

  C.數(shù)字化壓縮編碼   D.電子合成波形

  (52)A.屬于MTV B.有極高保真度 C.經(jīng)過(guò)三次編碼處理 D.經(jīng)數(shù)字化壓縮編碼

  (53)A.描述音樂(lè)演奏過(guò)程的指令  B.音樂(lè)電信號(hào)的采樣數(shù)值

  C.分成許多小段的音樂(lè)    D.多聲道電子合成的音樂(lè)

  (54)A.幀內(nèi)圖像數(shù)據(jù)壓縮     B.幀間圖像數(shù)據(jù)壓縮

  C.富里哀變換        D.霍夫曼編碼

  (55)A.圖像的大小 B.圖像的色彩 C.圖像袁現(xiàn)的細(xì)節(jié) D.圖像序列變化的程度

  ●_(56)_是軟件過(guò)程評(píng)估的國(guó)際標(biāo)準(zhǔn),可以樁任何組織用于軟件的設(shè)計(jì);管理、監(jiān)督、控制以及提高獲得、供應(yīng)、開發(fā)、操作、升級(jí)和支持的能力。IS09000系列標(biāo)準(zhǔn)是國(guó)際標(biāo)準(zhǔn)化組織質(zhì)量管理和質(zhì)量保證技術(shù)委員會(huì)于_(57)_年頒布的質(zhì)量管理和質(zhì)量保證系列標(biāo)準(zhǔn)。

  目前,IS09000、2000系列標(biāo)準(zhǔn)它包括_(58)_項(xiàng)具體標(biāo)準(zhǔn)。_(59)_是軟件生命周期過(guò)程的國(guó)際標(biāo)準(zhǔn)。

  (56)A.ISO/IECl5504  B.IS012207  C.SA-CMM  D.CMM

  (57)A.1987      B.1990    C.1994   D.2000

  (58)A.4     B.5   C.16  D.20

  (59)A.ISO/PECl5504  B.IS012207  C.SA CMM  D.CMM

  ●局部用戶所使用的數(shù)據(jù)可以不參與到全局?jǐn)?shù)據(jù)庫(kù)中去,這種特性屬于_(60)_。

  (60)A.數(shù)據(jù)的集中控制性 B.數(shù)據(jù)的獨(dú)立性 C.場(chǎng)地自治性 D.數(shù)據(jù)冗余可控性

  ●某循環(huán)冗余碼(CRC)的生成多項(xiàng)式為G(X)=x5+x4+x+1,則它對(duì)任意長(zhǎng)度的信息位產(chǎn)生_(61)_位長(zhǎng)的冗余位,并可檢驗(yàn)出所有突發(fā)長(zhǎng)度_(62)_位的突發(fā)錯(cuò)誤。若信息位于1010100,采用此生多項(xiàng)產(chǎn)生冗余位,加在信息位后形成的碼字是_(63)_。在讀出或接收端讀到的碼字中若不滿足某種規(guī)律可判斷其必然有錯(cuò)。例如_(64)_和_(65)_就是出錯(cuò)的碼字。

  (61)A.小于等于4 B.4 C.小于等于5 D.5 E.大于等于5 F.大于5

  (62)A.小于等于4 B.4 C.小于等于5 D.5 E.大于等于5 F.大于5

  (63)A.1010110111111    B.1010111010001

  C.1010110001101    D.1010111101010

  E.1010111011001    F.1010110001100

  (64)A.1010110111111    B.1010111010001

  C.1010110001101    D.1010111101010

  E.1010111011001    F.1010110001100

  (65)A.1010110111111    B.1010111010001

  C.1010110001101    D.1010111101010

  E.1010111011001    F.1010110001100

  ●Typically,these are concerm with the establishment of _(66)_ the network and with the control of the flow of messages across this channel. The provision of such facilities is only part of the network requirements,however,since in many applications the communicating computers may be of different types. This means that they may use different programming languages and,more importantly,different forms of _(67)_ interface between user(application) prograrma,normally referred to,as application processes or APs,and the underlying communication services may be _(68)_ For example,one computer may be a smaall single- user computer,while another may be alarge _(69)_ system.In the earlier days of computer communication,these issues meant that only closed communities of computers(that is,from the same manufacturer) could communicate with each other in a meaningful way. IBM's Systems Network

  Architecture(SNA) and DEC's Digital Network Architecture (DNA) are just two examples of communication software packages produced by manufacturers to allow their systems to be int ercormected together.These proprietary packages, however, of which there am still many inexistence, do not address the problem of universal interconnect ability, or open systems interconnection. In an attempt to alleviate this problem,_(70)_,in the late 1970s,formulated a reference model to provide a common basis (or the coordination of standards developments and to allow existing and evolving standards acivities to be placed into perspective with one another.

  (66)A.communication channel access  B.protocols

  C.datachanneI           D.public communieation

  (67)A.database            B.data representation

  C.protocols            D.data communication

  (68)A.same    B.similar  C.different   D.dependent

  (69)A.multi-user B.client   C.server    D.full-user

  (70)A.DNA     B.SNA    C.the OSI    D.the ISO

  ●One of the functions of the _(71)_ is to store the applications progrms {or the various secondaries. The _(72)_ may have similar or dissimilar functions. The same control code received from two different secondaries may warrant two different actions on the part of the host computer. If the system so requires,the host computer must also provide _(73)_ for the centralized data and the software for database management. Data information is normally stored in auxiliary memories to which the computer has ready access. The_(74)_ peripherals connected to the host computer allow for human entry and intervention. As needs change, application programs may require additions, deletions, or changes. Data link problems also arise which are __(75)_ the range of the computer's programmed capabilities. In such cases, human entry is required to make the necessary changes to resolve the existing problems.

  (71)A.peripherals  B.host computer  C.the interface  D.the client

  (72)A.set      B.host       C.secondaries   D.record

  (73)A.storage    B.data       C.range      D.link

  (74)A.peripherals  B.database     C.the interface  D.clients

  (75)A.dose to    B.during      C.within      D.beyond

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